最右Sign算法分析
密文:
0000: 37 63 62 32 66 38 61 30 30 63 30 64 64 62 32 62 7cb2f8a00c0ddb2b0010: 33 66 63 61 30 32 63 31 66 39 32 37 32 35 30 36 3fca02c1f9272506开启详细日志
Logger.getLogger(DalvikVM64.class).setLevel(Level.DEBUG);得到newStringUTF数据地址 0x4041e2f0
traceWrite
emulator.traceWrite(0x4041e2f0, 0x4041E312);得到日志:
[11:10:40 213] Memory WRITE at 0x4041e2f0, data size = 8, data value = 0x66326263372d3276, PC=RX@0x401fc184[libc.so]0x1c184, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 213] Memory WRITE at 0x4041e2f8, data size = 8, data value = 0x6464306330306138, PC=RX@0x401fc184[libc.so]0x1c184, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 213] Memory WRITE at 0x4041e300, data size = 8, data value = 0x3061636633623262, PC=RX@0x401fc18c[libc.so]0x1c18c, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 213] Memory WRITE at 0x4041e308, data size = 8, data value = 0x3237323966316332, PC=RX@0x401fc18c[libc.so]0x1c18c, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 213] Memory WRITE at 0x4041e303, data size = 8, data value = 0x3163323061636633, PC=RX@0x401fc1a4[libc.so]0x1c1a4, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 214] Memory WRITE at 0x4041e30b, data size = 8, data value = 0x3630353237323966, PC=RX@0x401fc1a4[libc.so]0x1c1a4, LR=RX@0x40019210[libnet_crypto.so]0x19210[11:10:40 214] Memory WRITE at 0x4041e2f0, data size = 8, data value = 0x000000004041e320, PC=RX@0x4005a704[libnet_crypto.so]0x5a704, LR=RX@0x4005a6fc[libnet_crypto.so]0x5a6fcv2-7cb2f8a00c0ddb2b3fca02c1f9272506可以看到PC指向lbc里的函数,打开libc,跳进去,发现是memcpy函数
Hook Memcpy
public void hookMemcpy() { Debugger debugger = emulator.attach(); debugger.addBreakPoint(module.findSymbolByName("memcpy").getAddress(), (emulator, address) -> { RegisterContext context = emulator.getContext(); UnidbgPointer arg0 = context.getPointerArg(0); UnidbgPointer arg1 = context.getPointerArg(1); int arg2 = context.getIntArg(2); Inspector.inspect( arg1.getByteArray(0, arg2), "memcpy" + " 写入地址 " + "0x" + Long.toHexString(arg0.peer) + " 读取地址 " + "0x" + Long.toHexString(arg1.peer) ); return true; }); }日志:
[11:10:40 213]memcpy 写入地址 0x4041e2f0 读取地址 0x4041e2c0, md5=ea19938ff8811853b04966b7379861f8, hex=76322d3763623266386130306330646462326233666361303263316639323732353036size: 350000: 76 32 2D 37 63 62 32 66 38 61 30 30 63 30 64 64 v2-7cb2f8a00c0dd0010: 62 32 62 33 66 63 61 30 32 63 31 66 39 32 37 32 b2b3fca02c1f92720020: 35 30 36 506^-----------------------------------------------------------------------------^可以看到读取地址在0x4041e2c0,接着监控一下这块内存的写入
emulator.traceWrite(0x4041e2c0, 0x4041e2e2);部分日志
[12:42:02 493] Memory WRITE at 0x4041e2c0, data size = 1, data value = 0x37, PC=RX@0x4003100c[libnet_crypto.so]0x3100c, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c1, data size = 1, data value = 0x63, PC=RX@0x4003100c[libnet_crypto.so]0x3100c, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c2, data size = 1, data value = 0x62, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c3, data size = 1, data value = 0x32, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c4, data size = 1, data value = 0x66, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c5, data size = 1, data value = 0x38, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c6, data size = 1, data value = 0x61, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c7, data size = 1, data value = 0x30, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4[12:42:02 493] Memory WRITE at 0x4041e2c8, data size = 1, data value = 0x30, PC=RX@0x40031024[libnet_crypto.so]0x31024, LR=RX@0x40030ec4[libnet_crypto.so]0x30ec40x37是我们密文的第一个字节,对应的日志输出了PC和LR的地址PC=RX@0x4003100c[libnet_crypto.so]0x3100c LR=RX@0x40030ec4[libnet_crypto.so]0x30ec4
先看指向的函数:
void *__usercall sub_30C94@<X0>(unsigned __int8 *a1@<X0>, _QWORD *n1228256393@<X8>){ void *n1228256393_1; // x0 const void *v5; // x21 void *v6; // x22 int n1554935301; // w25 int n1554935301_1; // w9 signed __int64 v9; // x8 int n1554935301_2; // w10 bool v11; // zf signed __int64 v12; // x8 size_t v13; // x23 int n1466722806; // w27 int n1466722806_1; // w9 int n1466722806_2; // w8 __int64 v17; // x8 __int64 n32; // x9 unsigned int v19; // t1 __int64 v20; // x13 __int64 v21; // x14
_ReadStatusReg(TPIDR_EL0); n1228256393[4] = n1228256393; n1228256393[5] = n1228256393; n1228256393_1 = n1228256393; if ( (int)n1228256393 <= 1228256393 && (_DWORD)n1228256393 != 1059521444 ) std::__stl_throw_length_error(&byte_9B5F4); *(_BYTE *)n1228256393 = 0; if ( n1228256393[4] - n1228256393[5] > 0x1Fu ) { v5 = (const void *)n1228256393[4]; v6 = (void *)(n1228256393[5] + 32LL); if ( v6 == v5 ) n1554935301 = -1086414335; else n1554935301 = 1554935301; n1554935301_1 = -666440926; v9 = n1228256393[4]; while ( 1 ) { do { n1554935301_2 = n1554935301_1; v11 = n1554935301_1 == -666440926; n1554935301_1 = n1554935301; } while ( v11 ); if ( n1554935301_2 == -1086414335 ) break; if ( n1554935301_2 != 1554935301 ) { while ( 1 ) ; } v12 = v9 - (_QWORD)v5; v13 = v12 + 1; if ( v12 == -1 ) n1466722806 = -2068670317; else n1466722806 = 1466722806; for ( n1466722806_1 = -2093236247; ; n1466722806_1 = -2068670317 ) { do { n1466722806_2 = n1466722806_1; v11 = n1466722806_1 == -2093236247; n1466722806_1 = n1466722806; } while ( v11 ); if ( n1466722806_2 != 1466722806 ) break; n1228256393_1 = memmove(v6, v5, v13); } if ( n1466722806_2 != -2068670317 ) { while ( 1 ) ; } v9 = n1228256393[4] + (_BYTE *)v6 - (_BYTE *)v5; n1228256393[4] = v9; n1554935301_1 = -1086414335; } } else { n1228256393_1 = (void *)sub_311F4( (int)n1228256393, -669595639 - *((_DWORD *)n1228256393 + 8) + *((_DWORD *)n1228256393 + 10) + 669595671, 0); } v17 = 0; // 主要看这部分 a567def8901234a 是个表: // .rodata:000000000006D680 a567def8901234a DCB "567def8901234abc",0 // ================================================= for ( n32 = 0; n32 != 32; n32 += 2 ) { v19 = *a1++; ++v17; *(_BYTE *)(n1228256393[5] + n32) = a567def8901234a[(unsigned __int64)v19 >> 4]; v20 = n32 & 1; v21 = n32 ^ 1; *(_BYTE *)(n1228256393[5] + (v20 | v21)) = a567def8901234a[v19 & 0xF]; } // ================================================= _ReadStatusReg(TPIDR_EL0); return n1228256393_1;}经过了一些混淆,但不难看出这是个将一个32字节的数据转换为64字符的十六进制字符串表示形式的函数,并且码表经过了修改,正常应该是0123456789abcdef,这里留个心
验证一下:
emulator.attach().addBreakPoint(module.base + 0x30C94);结果:
mx0
>-----------------------------------------------------------------------------<[12:48:20 739]x0=unidbg@0xbffff5a8, md5=5d5d1b1e60f18c4e645a0bfcc67a25bf, hex=2fea56d88f833eaeb5fd8af957a2a081000000000000000090e14140000000004016feff00000000f0f6ffbf00000000c48a01400000000020f6ffbf00000000ccd103400000000090e141400000000096e1414000000000a0e141400000000040c10940000000000000000000000000size: 1120000: 2F EA 56 D8 8F 83 3E AE B5 FD 8A F9 57 A2 A0 81 /.V...>.....W...0010: 00 00 00 00 00 00 00 00 90 E1 41 40 00 00 00 00 ..........A@....0020: 40 16 FE FF 00 00 00 00 F0 F6 FF BF 00 00 00 00 @...............0030: C4 8A 01 40 00 00 00 00 20 F6 FF BF 00 00 00 00 ...@.... .......0040: CC D1 03 40 00 00 00 00 90 E1 41 40 00 00 00 00 ...@......A@....0050: 96 E1 41 40 00 00 00 00 A0 E1 41 40 00 00 00 00 ..A@......A@....0060: 40 C1 09 40 00 00 00 00 00 00 00 00 00 00 00 00 @..@............^-----------------------------------------------------------------------------^2F EA 56 D8 8F 83 3E AE B5 FD 8A F9 57 A2 A0 81 这一段第一次分析可能没啥头绪,但我分析过老版本的最右,这一段其实是魔改iv的MD5加密之后的结果(明文是123456),但是我们的密文是:
0000: 37 63 62 32 66 38 61 30 30 63 30 64 64 62 32 62 7cb2f8a00c0ddb2b0010: 33 66 63 61 30 32 63 31 66 39 32 37 32 35 30 36 3fca02c1f9272506显然差的有点多,但是长度是一致的,结合刚刚的发现,这里的码表被修改过,会不会是码表被修改了,导致结果变了呢?我们来尝试一下即可
public static String byteHEX(byte ib) { /*char[] Digit = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f' };*/ char[] Digit = "567def8901234abc".toCharArray(); char[] ob = new char[2]; ob[0] = Digit[(ib >>> 4) & 0X0F]; ob[1] = Digit[ib & 0X0F]; String s = new String(ob); return s; }确实输出了我们想要的值7cb2f8a00c0ddb2b3fca02c1f9272506,那么接下来就是分析2fea56d88f833eaeb5fd8af957a2a081值的由来了(上面说了,是个魔改MD5==)
当然你可能没分析过老版本的,那也没关系,我们来定位一下这段数据的生成位置。可以看到日志中显示x0=unidbg@0xbffff5a8,我们监控一下这段内存的读写(当然我第一次并不是这么分析的,这段数据怀疑是MD5,直接在trace日志里搜K表可以直接定位到MD5函数)
emulator.traceWrite(0xbffff5a8L, 0xbffff5c7L);日志:
[12:56:55 035] Memory WRITE at 0xbffff5a8, data size = 8, data value = 0xae3e838fd856ea2f, PC=RX@0x40030c0c[libnet_crypto.so]0x30c0c, LR=RX@0x40030b68[libnet_crypto.so]0x30b68[12:56:55 035] Memory WRITE at 0xbffff5b0, data size = 8, data value = 0x81a0a257f98afdb5, PC=RX@0x40030c0c[libnet_crypto.so]0x30c0c, LR=RX@0x40030b68[libnet_crypto.so]0x30b68[12:56:55 038] Memory WRITE at 0xbffff5a8, data size = 8, data value = 0x0000000000000000, PC=RX@0x400194fc[libnet_crypto.so]0x194fc, LR=RX@0x40018ad8[libnet_crypto.so]0x18ad8[12:56:55 038] Memory WRITE at 0xbffff5b0, data size = 8, data value = 0x00000000383e5149, PC=RX@0x40019500[libnet_crypto.so]0x19500, LR=RX@0x40018ad8[libnet_crypto.so]0x18ad8[12:56:55 038] Memory WRITE at 0xbffff5b8, data size = 8, data value = 0x0000000000000000, PC=RX@0x40019500[libnet_crypto.so]0x19500, LR=RX@0x40018ad8[libnet_crypto.so]0x18ad8[12:56:55 038] Memory WRITE at 0xbffff5c0, data size = 8, data value = 0x000000004041e190, PC=RX@0x40019504[libnet_crypto.so]0x19504, LR=RX@0x40018ad8[libnet_crypto.so]0x18ad8PC和LR指向同一函数,下个断点看看,日志:
mx1
>-----------------------------------------------------------------------------<[13:17:34 567]x1=unidbg@0xbffff520, md5=d7c8f8218c4dabbf9abe28c8a39927d7, hex=0123556789abcdedfedeba987654321630000000000000003132333435360000d0f5ffbf0000000074e101400000000000f6ffbf00000000070000000000000086e141400000000107000000000000001000000000000001000000000000000038f6ffbf000000000000000000000000size: 1120000: 01 23 55 67 89 AB CD ED FE DE BA 98 76 54 32 16 .#Ug........vT2.0010: 30 00 00 00 00 00 00 00 31 32 33 34 35 36 00 00 0.......123456..0020: D0 F5 FF BF 00 00 00 00 74 E1 01 40 00 00 00 00 ........t..@....0030: 00 F6 FF BF 00 00 00 00 07 00 00 00 00 00 00 00 ................0040: 86 E1 41 40 00 00 00 01 07 00 00 00 00 00 00 00 ..A@............0050: 10 00 00 00 00 00 00 01 00 00 00 00 00 00 00 00 ................0060: 38 F6 FF BF 00 00 00 00 00 00 00 00 00 00 00 00 8...............^-----------------------------------------------------------------------------^第一行其实是四个iv(后续会解释),第二行是明文,blr下个断点,c继续执行,查看X0
m0xbffff5a8
>-----------------------------------------------------------------------------<[13:18:51 555]unidbg@0xbffff5a8, md5=5d5d1b1e60f18c4e645a0bfcc67a25bf, hex=2fea56d88f833eaeb5fd8af957a2a081000000000000000090e14140000000004016feff00000000f0f6ffbf00000000c48a01400000000020f6ffbf00000000ccd103400000000090e141400000000096e1414000000000a0e141400000000040c10940000000000000000000000000size: 1120000: 2F EA 56 D8 8F 83 3E AE B5 FD 8A F9 57 A2 A0 81 /.V...>.....W...0010: 00 00 00 00 00 00 00 00 90 E1 41 40 00 00 00 00 ..........A@....0020: 40 16 FE FF 00 00 00 00 F0 F6 FF BF 00 00 00 00 @...............0030: C4 8A 01 40 00 00 00 00 20 F6 FF BF 00 00 00 00 ...@.... .......0040: CC D1 03 40 00 00 00 00 90 E1 41 40 00 00 00 00 ...@......A@....0050: 96 E1 41 40 00 00 00 00 A0 E1 41 40 00 00 00 00 ..A@......A@....0060: 40 C1 09 40 00 00 00 00 00 00 00 00 00 00 00 00 @..@............^-----------------------------------------------------------------------------^第一行就是密文了,看来加密就是在这个函数里进行的了,静态分析一下吧
void *__fastcall sub_30850(_OWORD *a1, char *a2){ __int64 v2; // x8 int v3; // w23 char *v4; // x10 int n16; // w8 int v6; // w9 unsigned __int8 *v7; // x10 int v8; // w11 int n1216331821; // w11 int n14; // w10 int v11; // w8 unsigned __int8 *v12; // x14 int v13; // w15 int v14; // w17 int v15; // w10 int n1216331821_1; // w15 unsigned __int8 *v17; // x8 int n4; // w9 int v19; // w10 char *v23; // [xsp+10h] [xbp-80h] _DWORD *v24; // [xsp+18h] [xbp-78h] char *v25; // [xsp+20h] [xbp-70h] _QWORD *v26; // [xsp+28h] [xbp-68h] void *v27; // [xsp+30h] [xbp-60h] unsigned int n8; // [xsp+3Ch] [xbp-54h]
v23 = a2 + 16; v24 = a2 + 16; v25 = a2 + 24; v2 = ((*((_DWORD *)a2 + 4) >> 3) ^ 0x1FFFFFC0u) & (*((_DWORD *)a2 + 4) >> 3); v26 = a2 + 24; v3 = -931151827; v4 = &a2[v2 + 24]; v27 = v4 + 1; *v4 = 0x80; n8 = v2 ^ 0x3F; if ( n8 >= 8 ) { memset(v27, 0, n8 - 8); } else { memset(v27, 0, n8); n16 = 16; v6 = -15; v7 = (unsigned __int8 *)v26 + 1; v8 = -931151827; while ( 1 ) { n1216331821 = v8 & 0x7FFFFFFF; if ( n1216331821 != 1216331821 ) break; --n16; if ( v6 ) v8 = -931151827; else v8 = -1953395755; *(_DWORD *)(v7 - 1) = (*(v7 - 1) | (*v7 << 8)) ^ 0x3CB3DB4F ^ ((v7[1] | (v7[2] << 8)) << 16) ^ 0x3CB3DB4F; v7 += 4; ++v6; } if ( n1216331821 != 194087893 ) { while ( 1 ) ; } sub_2E08C(a2, v26); v26[5] = 0; v26[6] = 0; v26[3] = 0; v26[4] = 0; v26[1] = 0; v26[2] = 0; *v26 = 0; } n14 = 14; v11 = -13; v12 = (unsigned __int8 *)v26 + 1; v13 = -931151827; while ( 1 ) { n1216331821_1 = v13 & 0x7FFFFFFF; if ( n1216331821_1 != 1216331821 ) break; v15 = n14 + 1683802602; if ( v11 ) v13 = -931151827; else v13 = -1953395755; n14 = v15 - 1683802603; v14 = (v12[1] | (v12[2] << 8)) << 16; *(_DWORD *)(v12 - 1) = (*v12 << 8) ^ 0xD8724FCC ^ *(v12 - 1) ^ 0xD8724FCC ^ 0x11287F8 ^ v14 ^ 0x11287F8 | ~((*v12 << 8) ^ 0xD8724FCC ^ ~(*(v12 - 1) ^ 0xD8724FCC) | ~v14); v12 += 4; ++v11; } if ( n1216331821_1 != 194087893 ) { while ( 1 ) ; } *((_DWORD *)v25 + 14) = *v24; *((_DWORD *)v25 + 15) = *((_DWORD *)v23 + 1); sub_2E08C(a2, v26); v17 = (unsigned __int8 *)(a2 + 1); n4 = 4; v19 = -3; while ( (v3 & 0x7FFFFFFF) == 0x487FC02D ) { --n4; if ( v19 ) v3 = -931151827; else v3 = -1953395755; *(_DWORD *)(v17 - 1) = (unsigned __int16)(*(v17 - 1) | (*v17 << 8)) | (((unsigned __int16)(v17[2] << 8) ^ 0x9DB8 ^ v17[1] ^ 0x9DB8) << 16); v17 += 4; ++v19; } if ( (v3 & 0x7FFFFFFF) != 0xB918BD5 ) { while ( 1 ) ; } *a1 = *(_OWORD *)a2; return memset(a2, 0, 0x58u);}主要盯着a2看就行了,其中sub_2E08C(a2, v26);函数调用了两次,点进去看可以发现是个运算函数,有六七百行,就不贴了,下个断点看看。日志:
mx0
>-----------------------------------------------------------------------------<[13:23:01 005]x0=unidbg@0xbffff520, md5=bcc59f26ae8410ea5c781da852f0e9f6, hex=0123556789abcdedfedeba9876543216300000000000000031323334353680000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000003000000000000000000000000000000038f6ffbf000000000000000000000000size: 1120000: 01 23 55 67 89 AB CD ED FE DE BA 98 76 54 32 16 .#Ug........vT2.0010: 30 00 00 00 00 00 00 00 31 32 33 34 35 36 80 00 0.......123456..0020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................0030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................0040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................0050: 30 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0...............0060: 38 F6 FF BF 00 00 00 00 00 00 00 00 00 00 00 00 8...............^-----------------------------------------------------------------------------^mx1
>-----------------------------------------------------------------------------<[13:23:03 393]x1=unidbg@0xbffff538, md5=582ff5d679cd51d5a67525e36e29daf4, hex=31323334353680000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000003000000000000000000000000000000038f6ffbf000000000000000000000000d0f5ffbf00000000c41103400000000001a23ebf00000000size: 1120000: 31 32 33 34 35 36 80 00 00 00 00 00 00 00 00 00 123456..........0010: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................0020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................0030: 00 00 00 00 00 00 00 00 30 00 00 00 00 00 00 00 ........0.......0040: 00 00 00 00 00 00 00 00 38 F6 FF BF 00 00 00 00 ........8.......0050: 00 00 00 00 00 00 00 00 D0 F5 FF BF 00 00 00 00 ................0060: C4 11 03 40 00 00 00 00 01 A2 3E BF 00 00 00 00 ...@......>.....^-----------------------------------------------------------------------------^参数1是四个iv,参数二是明文。为什么参数一是iv?因为之前分析过老版本。。。没分析过的话,那就是因为输出32位,所以合理怀疑是MD5,看一下代码,有这么一段:
v319 = *a1; v315 = a1[3]; v316 = a1[1]; v317 = a1[2];................. v24 = v319 - 680876936 + *a2 + (v315 & (v315 ^ 0x1FE328B9 ^ ~(v317 ^ 0x1FE328B9) | ~v316) | ~(v315 ^ 0x1FE328B9 ^ ~(v317 ^ 0x1FE328B9) | ~v316) & ~v315); v25 = ((v24 << 7) ^ 0x87CDF640 ^ (v24 >> 25) ^ 0x87CDF640) + v316; v26 = v16 - 176418897 + v25; v27 = (v317 & (~v25 | ~(v317 ^ 0x1C9A5715 ^ v316 ^ 0x1C9A5715)) | ~(~v25 | ~(v317 ^ 0x1C9A5715 ^ v316 ^ 0x1C9A5715)) & ~v317) - (-v8 - (v315 - 389564586));..................像是在给iv赋值并参与计算。怀疑的成本很低,大不了验证一下,验证之后输出的结果却是是一模一样的
四个iv:
state[0] = 0x67552301L;state[1] = 0xEDCDAB89L;state[2] = 0x98BADEFEL;state[3] = 0x16325476L;至此分析结束,就是魔改了tohex的码表和md5的iv,别的也没啥
因为是边分析边写的,有的地方比较乱,不过应该还是能看懂的。比较简单的一个参数
贴下代码吧:
package com.yuuki.zuiyou;
import com.github.unidbg.AndroidEmulator;import com.github.unidbg.Emulator;import com.github.unidbg.Module;import com.github.unidbg.arm.backend.Unicorn2Factory;import com.github.unidbg.arm.context.RegisterContext;import com.github.unidbg.debugger.BreakPointCallback;import com.github.unidbg.debugger.Debugger;import com.github.unidbg.hook.hookzz.*;import com.github.unidbg.linux.android.AndroidEmulatorBuilder;import com.github.unidbg.linux.android.AndroidResolver;import com.github.unidbg.linux.android.dvm.*;import com.github.unidbg.memory.Memory;import com.github.unidbg.pointer.UnidbgPointer;import com.github.unidbg.utils.Inspector;import com.github.unidbg.virtualmodule.android.AndroidModule;import org.apache.log4j.Level;import org.apache.log4j.Logger;
import java.io.File;import java.io.PrintStream;import java.nio.charset.StandardCharsets;import java.nio.file.Files;import java.nio.file.Paths;
public class zuiyou extends AbstractJni { private final String packageName = "cn.xiaochuankeji.tieba"; private final String apkName = "zuiyou"; private final String libName = "libnet_crypto.so";
private final AndroidEmulator emulator; private final VM vm; private DalvikModule dm; private Module module;
DvmClass NetCrypto;
public zuiyou() { emulator = AndroidEmulatorBuilder .for64Bit() .addBackendFactory(new Unicorn2Factory(true)) .setProcessName(packageName) .build(); Memory memory = emulator.getMemory(); memory.setLibraryResolver(new AndroidResolver(23)); vm = emulator.createDalvikVM(new File("apks/" + apkName + "/" + apkName + ".apk")); //vm.setVerbose(true); new AndroidModule(emulator, vm).register(memory); //new JniGraphics(emulator, vm).register(memory); vm.setJni(this); dm = vm.loadLibrary(new File("apks/" + apkName + "/" + libName), false); module = dm.getModule();
//emulator.traceWrite(0x4041e2f0, 0x4041E312);
dm.callJNI_OnLoad(emulator);
NetCrypto = vm.resolveClass("com/izuiyou/network/NetCrypto"); }
public void hookMemcpy() { Debugger debugger = emulator.attach(); debugger.addBreakPoint(module.findSymbolByName("memcpy").getAddress(), (emulator, address) -> { RegisterContext context = emulator.getContext(); UnidbgPointer arg0 = context.getPointerArg(0); UnidbgPointer arg1 = context.getPointerArg(1); int arg2 = context.getIntArg(2); Inspector.inspect( arg1.getByteArray(0, arg2), "memcpy" + " 写入地址 " + "0x" + Long.toHexString(arg0.peer) + " 读取地址 " + "0x" + Long.toHexString(arg1.peer) ); return true; }); }
public void hookMemmove() { Debugger debugger = emulator.attach(); debugger.addBreakPoint(module.findSymbolByName("memmove").getAddress(), (emulator, address) -> { RegisterContext context = emulator.getContext();
UnidbgPointer dst = context.getPointerArg(0); UnidbgPointer src = context.getPointerArg(1); int length = context.getIntArg(2);
Inspector.inspect( src.getByteArray(0, length), "memmove 写入地址 0x" + Long.toHexString(dst.peer) + " 读取地址 0x" + Long.toHexString(src.peer) );
return true; }); }
public void traceCode() { try { String traceFile = "apks/" + apkName + "/traceCode.log"; PrintStream traceStream = new PrintStream(Files.newOutputStream(Paths.get(traceFile)), true); emulator.traceCode().setRedirect(traceStream); } catch (java.io.IOException e) { System.out.println(e.getMessage()); } }
public void traceWrite() { try { String traceFile = "apks/" + apkName + "/traceWrite.log"; PrintStream traceStream = new PrintStream(Files.newOutputStream(Paths.get(traceFile)), true); emulator.traceWrite().setRedirect(traceStream); } catch (java.io.IOException e) { System.out.println(e.getMessage()); } }
public void traceRead() { try { String traceFile = "apks/" + apkName + "/traceRead.log"; PrintStream traceStream = new PrintStream(Files.newOutputStream(Paths.get(traceFile)), true); emulator.traceRead().setRedirect(traceStream); } catch (java.io.IOException e) { System.out.println(e.getMessage()); } }
public void nativeInit() { NetCrypto.callStaticJniMethod(emulator, "native_init()V"); }
public String callSign() { hookMemcpy(); hookMemmove(); //emulator.traceWrite(0x4041e2f0, 0x4041E312); emulator.traceWrite(0x4041e2c0, 0x4041e2e2); emulator.attach().addBreakPoint(module.base + 0x30C94); String arg1 = null; byte[] arg2 = "123456".getBytes(StandardCharsets.UTF_8); StringObject ret = NetCrypto.callStaticJniMethodObject(emulator, "sign(Ljava/lang/String;[B)Ljava/lang/String;", arg1, arg2); return ret.getValue(); // 拼接函数 sub_1973C x0 明文 x1密文 // xref -> sun_194F0
/* 0000: 37 63 62 32 66 38 61 30 30 63 30 64 64 62 32 62 7cb2f8a00c0ddb2b 0010: 33 66 63 61 30 32 63 31 66 39 32 37 32 35 30 36 3fca02c1f9272506 */ }
public static void main(String[] args) { //Logger.getLogger(DalvikVM64.class).setLevel(Level.DEBUG); // 0x4041e2f0 zuiyou zuiyou = new zuiyou(); zuiyou.nativeInit(); String res = zuiyou.callSign(); System.out.println(res); }}还原之后的算法:
package com.yuuki.YuukiUtils;
import java.lang.reflect.*;
public class MD5 { static final int S11 = 7; static final int S12 = 12; static final int S13 = 17; static final int S14 = 22;
static final int S21 = 5; static final int S22 = 9; static final int S23 = 14; static final int S24 = 20;
static final int S31 = 4; static final int S32 = 11; static final int S33 = 16; static final int S34 = 23;
static final int S41 = 6; static final int S42 = 10; static final int S43 = 15; static final int S44 = 21;
static final byte[] PADDING = { (byte)(0x80), 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; private final long[] state = new long[4]; // state (ABCD) private final long[] count = new long[2]; // number of bits, modulo 2^64 (lsb first) private final byte[] buffer = new byte[64]; // input buffer public String digestHexStr;
private final byte[] digest = new byte[16];
public String getMD5ofStr(String inbuf) { md5Init(); md5Update(inbuf.getBytes(), inbuf.length()); md5Final(); digestHexStr = ""; for (int i = 0; i < 16; i++) { digestHexStr += byteHEX(digest[i]); } return digestHexStr;
}
public MD5() { md5Init();
return; }
private void md5Init() { count[0] = 0L; count[1] = 0L; ///* Load magic initialization constants.
state[0] = 0x67552301L; state[1] = 0xEDCDAB89L; state[2] = 0x98BADEFEL; state[3] = 0x16325476L;
return; }
private long F(long x, long y, long z) { return (x & y) | ((~x) & z);
}
private long G(long x, long y, long z) { return (x & z) | (y & (~z));
}
private long H(long x, long y, long z) { return x ^ y ^ z; }
private long I(long x, long y, long z) { return y ^ (x | (~z)); }
private long FF(long a, long b, long c, long d, long x, long s, long ac) { a += F(b, c, d) + x + ac; a = ((long) (int) a << s) | ((int) a >>> (32 - s)); a += b; return a; }
private long GG(long a, long b, long c, long d, long x, long s, long ac) { a += G(b, c, d) + x + ac; a = ((long) (int) a << s) | ((int) a >>> (32 - s)); a += b; return a; }
private long HH(long a, long b, long c, long d, long x, long s, long ac) { a += H(b, c, d) + x + ac; a = ((long) (int) a << s) | ((int) a >>> (32 - s)); a += b; return a; }
private long II(long a, long b, long c, long d, long x, long s, long ac) { a += I(b, c, d) + x + ac; a = ((long) (int) a << s) | ((int) a >>> (32 - s)); a += b; return a; }
private void md5Update(byte[] inbuf, int inputLen) {
int i, index, partLen; //byte[] block = new byte[64]; index = (int) (count[0] >>> 3) & 0x3F; // /* Update number of bits */ if ((count[0] += ((long) inputLen << 3)) < ((long) inputLen << 3)) count[1]++; count[1] += (inputLen >>> 29);
partLen = 64 - index;
// Transform as many times as possible. if (inputLen >= partLen) { md5Memcpy(buffer, inbuf, index, 0, partLen); md5Transform(buffer);
for (i = partLen; i + 63 < inputLen; i += 64) {
//md5Memcpy(block, inbuf, 0, i, 64); //md5Transform(block); md5Memcpy(buffer, inbuf, 0, i, 64); md5Transform(buffer); } index = 0;
} else
i = 0;
///* Buffer remaining input */ md5Memcpy(buffer, inbuf, index, i, inputLen - i);
}
private void md5Final() { byte[] bits = new byte[8]; int index, padLen;
///* Save number of bits */ Encode(bits, count, 8);
///* Pad out to 56 mod 64. index = (int) (count[0] >>> 3) & 0x3f; padLen = (index < 56) ? (56 - index) : (120 - index); md5Update(PADDING, padLen);
///* Append length (before padding) */ md5Update(bits, 8);
///* Store state in digest */ Encode(digest, state, 16);
}
private void md5Memcpy(byte[] output, byte[] input, int outpos, int inpos, int len) { int i;
for (i = 0; i < len; i++) output[outpos + i] = input[inpos + i]; }
private void md5Transform(byte[] block) { long a = state[0], b = state[1], c = state[2], d = state[3]; long[] x = new long[16];
Decode(x, block, 64);
/* Round 1 */ a = FF(a, b, c, d, x[0], S11, 0xd76aa478L); /* 1 */ d = FF(d, a, b, c, x[1], S12, 0xe8c7b756L); /* 2 */ c = FF(c, d, a, b, x[2], S13, 0x242070dbL); /* 3 */ b = FF(b, c, d, a, x[3], S14, 0xc1bdceeeL); /* 4 */ a = FF(a, b, c, d, x[4], S11, 0xf57c0fafL); /* 5 */ d = FF(d, a, b, c, x[5], S12, 0x4787c62aL); /* 6 */ c = FF(c, d, a, b, x[6], S13, 0xa8304613L); /* 7 */ b = FF(b, c, d, a, x[7], S14, 0xfd469501L); /* 8 */ a = FF(a, b, c, d, x[8], S11, 0x698098d8L); /* 9 */ d = FF(d, a, b, c, x[9], S12, 0x8b44f7afL); /* 10 */ c = FF(c, d, a, b, x[10], S13, 0xffff5bb1L); /* 11 */ b = FF(b, c, d, a, x[11], S14, 0x895cd7beL); /* 12 */ a = FF(a, b, c, d, x[12], S11, 0x6b901122L); /* 13 */ d = FF(d, a, b, c, x[13], S12, 0xfd987193L); /* 14 */ c = FF(c, d, a, b, x[14], S13, 0xa679438eL); /* 15 */ b = FF(b, c, d, a, x[15], S14, 0x49b40821L); /* 16 */
/* Round 2 */ a = GG(a, b, c, d, x[1], S21, 0xf61e2562L); /* 17 */ d = GG(d, a, b, c, x[6], S22, 0xc040b340L); /* 18 */ c = GG(c, d, a, b, x[11], S23, 0x265e5a51L); /* 19 */ b = GG(b, c, d, a, x[0], S24, 0xe9b6c7aaL); /* 20 */ a = GG(a, b, c, d, x[5], S21, 0xd62f105dL); /* 21 */ d = GG(d, a, b, c, x[10], S22, 0x2441453L); /* 22 */ c = GG(c, d, a, b, x[15], S23, 0xd8a1e681L); /* 23 */ b = GG(b, c, d, a, x[4], S24, 0xe7d3fbc8L); /* 24 */ a = GG(a, b, c, d, x[9], S21, 0x21e1cde6L); /* 25 */ d = GG(d, a, b, c, x[14], S22, 0xc33707d6L); /* 26 */ c = GG(c, d, a, b, x[3], S23, 0xf4d50d87L); /* 27 */ b = GG(b, c, d, a, x[8], S24, 0x455a14edL); /* 28 */ a = GG(a, b, c, d, x[13], S21, 0xa9e3e905L); /* 29 */ d = GG(d, a, b, c, x[2], S22, 0xfcefa3f8L); /* 30 */ c = GG(c, d, a, b, x[7], S23, 0x676f02d9L); /* 31 */ b = GG(b, c, d, a, x[12], S24, 0x8d2a4c8aL); /* 32 */
/* Round 3 */ a = HH(a, b, c, d, x[5], S31, 0xfffa3942L); /* 33 */ d = HH(d, a, b, c, x[8], S32, 0x8771f681L); /* 34 */ c = HH(c, d, a, b, x[11], S33, 0x6d9d6122L); /* 35 */ b = HH(b, c, d, a, x[14], S34, 0xfde5380cL); /* 36 */ a = HH(a, b, c, d, x[1], S31, 0xa4beea44L); /* 37 */ d = HH(d, a, b, c, x[4], S32, 0x4bdecfa9L); /* 38 */ c = HH(c, d, a, b, x[7], S33, 0xf6bb4b60L); /* 39 */ b = HH(b, c, d, a, x[10], S34, 0xbebfbc70L); /* 40 */ a = HH(a, b, c, d, x[13], S31, 0x289b7ec6L); /* 41 */ d = HH(d, a, b, c, x[0], S32, 0xeaa127faL); /* 42 */ c = HH(c, d, a, b, x[3], S33, 0xd4ef3085L); /* 43 */ b = HH(b, c, d, a, x[6], S34, 0x4881d05L); /* 44 */ a = HH(a, b, c, d, x[9], S31, 0xd9d4d039L); /* 45 */ d = HH(d, a, b, c, x[12], S32, 0xe6db99e5L); /* 46 */ c = HH(c, d, a, b, x[15], S33, 0x1fa27cf8L); /* 47 */ b = HH(b, c, d, a, x[2], S34, 0xc4ac5665L); /* 48 */
/* Round 4 */ a = II(a, b, c, d, x[0], S41, 0xf4292244L); /* 49 */ d = II(d, a, b, c, x[7], S42, 0x432aff97L); /* 50 */ c = II(c, d, a, b, x[14], S43, 0xab9423a7L); /* 51 */ b = II(b, c, d, a, x[5], S44, 0xfc93a039L); /* 52 */ a = II(a, b, c, d, x[12], S41, 0x655b59c3L); /* 53 */ d = II(d, a, b, c, x[3], S42, 0x8f0ccc92L); /* 54 */ c = II(c, d, a, b, x[10], S43, 0xffeff47dL); /* 55 */ b = II(b, c, d, a, x[1], S44, 0x85845dd1L); /* 56 */ a = II(a, b, c, d, x[8], S41, 0x6fa87e4fL); /* 57 */ d = II(d, a, b, c, x[15], S42, 0xfe2ce6e0L); /* 58 */ c = II(c, d, a, b, x[6], S43, 0xa3014314L); /* 59 */ b = II(b, c, d, a, x[13], S44, 0x4e0811a1L); /* 60 */ a = II(a, b, c, d, x[4], S41, 0xf7537e82L); /* 61 */ d = II(d, a, b, c, x[11], S42, 0xbd3af235L); /* 62 */ c = II(c, d, a, b, x[2], S43, 0x2ad7d2bbL); /* 63 */ b = II(b, c, d, a, x[9], S44, 0xeb86d391L); /* 64 */
state[0] += a; state[1] += b; state[2] += c; state[3] += d;
}
private void Encode(byte[] output, long[] input, int len) { int i, j;
for (i = 0, j = 0; j < len; i++, j += 4) { output[j] = (byte) (input[i] & 0xffL); output[j + 1] = (byte) ((input[i] >>> 8) & 0xffL); output[j + 2] = (byte) ((input[i] >>> 16) & 0xffL); output[j + 3] = (byte) ((input[i] >>> 24) & 0xffL); } }
private void Decode(long[] output, byte[] input, int len) { int i, j;
for (i = 0, j = 0; j < len; i++, j += 4) output[i] = b2iu(input[j]) | (b2iu(input[j + 1]) << 8) | (b2iu(input[j + 2]) << 16) | (b2iu(input[j + 3]) << 24);
return; }
public static long b2iu(byte b) { return b < 0 ? b & 0x7F + 128 : b; }
public static String byteHEX(byte ib) { //char[] Digit = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f' }; char[] Digit = "567def8901234abc".toCharArray(); char[] ob = new char[2]; ob[0] = Digit[(ib >>> 4) & 0X0F]; ob[1] = Digit[ib & 0X0F]; String s = new String(ob); return s; }
public static void main(String[] args) {
MD5 m = new MD5(); System.out.println(m.getMD5ofStr("123456")); }
}周末快乐喵~